Big Idea 3.8 Hacks

We learned about for loops, while loops, do/while loops, and infinite loops. We also learned try and except. The hacks and homework helped me understand what type of loop to use, and how they would operate.

#Popcorn1
stu = input("Are you are student? Y/N ")
age = int(input("What is your age? "))
tix = 10

if stu == "Y":
    print("Students get a 10% discount")
    if 0 <= age <= 12:
        tix = tix * 0.5 * 0.2
    elif 12 <= age <= 63:
        tix = tix * 0.2
    elif age >= 65:
        tix = tix * 0.3 * 0.2
    else:
        print("Invalid age")
elif stu == "N":
    if 0 <= age <= 12:
        tix = tix * 0.5
    elif 12 <= age <= 63:
        tix = tix
    elif age >= 65:
        tix = tix * 0.3
    else:
        print("Invalid age")
else:
    print("Please try again")

print("Your ticket will cost", tix, "dollars. ")

#Popcorn2
try:
    num = int(input("Enter a number: "))  # Code that might raise an exception
    result = 10 / num  # Could raise ZeroDivisionError if num is 0
    print("Result:", result)
    if num % 2 != 0:
        print("odd")
    else:
        print("even")
except ValueError:
    print("That's not a valid number!")

'''
Create a program that asks the user for a number and keeps asking until they enter a positive number.

Requirements:

Input Validation: Make sure that the input is actually a number. Display an ‘error’ message if the user inputted something that is NOT a number
Positive Checker: If the user has entered a number that is positive, print a ‘success!’ message with the entered number
If the user has entered a number that is not positive like zero or a negative number, print a ‘try again’ message, prompting them to keep inputting numbers till they input a positive number.
'''
x = False
while x == False:
    try:
        num = int(input("Enter a number: "))  # Code that might raise an exception
        if num > 0:
            print("success")
            x = True
        else:
            print("try again")
    except ValueError:
        print("error")